12gm of an unknown gas exerts 2 atm pressure ,in a container of volume 5 dm3 at 227°C then calculate molar mass of unknown gas.
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As the volume is constant, pressure law can be applied, that is :
P2P1=T2T1
1.11=t+283t+273
t=−173∘C=100 K
Now, applying gas equation,
PV=nRT
or V=PnRT=120×112×0.082×100=0.82 litre
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