Question

-12k+3k=-18solve the following linear equation by trial and error as well as bye systematic method​

Answer 1

Answer:

k = 2

Step-by-step explanation:

By trial-and-error method:

LHS: Let k=1

 -12(1) + 3(1)

= -12+3

= -9

≠ RHS

LHS: Let k= 2

-12(2) + 3(2)

= -24+6

= -18

= RHS

By systematic method:

-12k + 3k = -18

⇒ -9k = -18

⇒ k = 2