12L of H2 and 11.2L of cl2 are mixed and exploded. The composition by volume of mixture is
Answers
Answer:
Since H2 was in excess, hence some part of it is unreacted. Therefore, the composition of the volume of mixtures is 22.4 litres of HCl and 0.8 litres of H2.
Explanation:
The balanced equation for this reaction is :
H
2
+Cl
2
→2HCl
1 mole of H
2
reacts with 1 mole of Cl
2
to give 2 moles of HCl.
Since 22.4 litres of a gas occupies 1 mole.
Hence, moles of 12 L of H
2
will be =
22.4
12
=0.54 moles
Similarly moles of 11.2 L Cl
2
gas =
22.4
11.2
=0.5 moles
Cl
2
is the limiting reagent it is present in a limited amount.
Therefore, 0.5 moles of the Cl
2
will give 1 mole of HCl.
Since H
2
was in excess, hence some part of it is unreacted.
So moles of unreacted H
2
is
22.4
12
−
22.4
11.2
=0.035 moles
Volume of unreacted H
2
is =0.035×22.4=0.8 litres
Therefore, the composition of the volume of mixtures is 22.4 litres of HCl and 0.8 litres of H
2
.