Question

-12m^5-m³+m factorise ​

Answer 1

Answer:

$-m(2m+1)(2m-1)(3m^2+1)$

Step-by-step explanation:

ma + mb = m(a+b)

a^2 + b^2 = (a+b)(a-b)

$-12m^{5} -m^{3} +m\\=m(-12m^{4} -m^{2} +1)$

$X=m^{2}$

$m(-12X^{2} -X+1)\\=-m(3X+1)(4X-1)\\=-m(2m+1)(2m-1)(3m^{2} +1)$