Question

12n^-2n-4 factroise​

Answer 1

STEP1 :

Equation at the end of step 1

((22•3n2) - 2n) - 4

STEP2:

STEP3:

Pulling out like terms

3.1 Pull out like factors :

12n2 - 2n - 4 = 2 • (6n2 - n - 2)

Trying to factor by splitting the middle term

3.2 Factoring 6n2 - n - 2

The first term is, 6n2 its coefficient is 6 .

The middle term is, -n its coefficient is -1 .

The last term, "the constant", is -2

Step-1 : Multiply the coefficient of the first term by the constant 6 • -2 = -12

Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is -1 .

-12 + 1 = -11

-6 + 2 = -4

-4 + 3 = -1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -4 and 3

6n2 - 4n + 3n - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

2n • (3n-2)

Add up the last 2 terms, pulling out common factors :

1 • (3n-2)

Step-5 : Add up the four terms of step 4 :

(2n+1) • (3n-2)

Which is the desired factorization

Final result :

2 • (3n - 2) • (2n + 1)