Question

સમીકરણ ઉકેલો: 12p - 11 = 25
1 + 5 (r - 1) = 34 સમીકરણનો ઉકેલ શોધો.
D​

Answer 1

$Given \: linear\: equation \: in \: one \\ variable\: p\: is \: 12p - 11 = 25$

/* Add bothsides of the equation by 11, we get */

$\impliez 12p - 11 + 11 = 25 + 11$

$\implies 12p = 36$

/* Dividing each term by 12, we get */

$\implies \frac{12p}{12} = \frac{36}{12}$

$\implies p = 3$

Therefore.,

$\red{ Value \: of\: p } \green { = 3 }$

$Given \: linear\: equation \: in \: one \\ variable\: p\: is \: 1 + 5(r-1) = 34$

/* subtract bothsides of the equation by 1, we get */

$\implies 1 + 5( r - 1) - 1 = 34 - 1$

$\implies 5( r - 1) = 33$

$\implies 5r - 5 = 33$

$\implies 5r = 33 + 5$

$\implies 5r = 38$

$\implies r = \frac{38}{5}$

Therefore.,

$\red{ Value \: of \:r }\green { = \frac{38}{5}}$

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