Question

12p^5+16p^4+12p^3
plzzz do it immediately​

Answer 1

Question :

➡ Factorise completely :

$12 {p}^{5} \: + 16 {p}^{4} - 20 {p}^{3}$

$\textbf {\underline {\underline {Step-By-Step\:Explanation:}}}$

$12 {p}^{5} + 16 {p}^{4} - 20 {p}^{3} \\ \\= (4 \times 3) {p}^{5} \: + (4 \times 4) {p}^{4} - (4 \times 5) {p}^{3}$

By taking $4p^3$ as common,

we get,

= $4 {p}^{3} (3 {p}^{2} + 4p - 5 \: )$

Now, It can't be factorised anymore. So, It's the final answer!

Answer :

$4p^3 ( 3p^2 + 4p - 5 )$