Question

12th any girls..find my question..intrigation (sin8x-cos8x)/(1-2sin2x.cos2x)

Answer 1

Let  f(x)=sin8x−cos8x1–2sin2xcos2x  

So, I=∫f(x)dx

=∫sin8x−cos8x1–2sin2xcos2xdx

=∫(sin4x+cos4x)(sin2x+cos2x)(sin2x−cos2x)(sin2x+cos2x)2–2sin2xcos2xdx

=∫(sin4x+cos4x)(sin2x−cos2x)sin4x+cos4xdx

=−∫cos(2x)dx

=−sin(2x)2+C

Where 'C' being arbitrary constants

Hope it helps u.

Answer 2

Heya.........✌✌

Answer for sin^8x - cos^8x/1-2sin^2xcos^2x is in attachment

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$\boxed{Thanx}$