Question

12th term from the end of the AP : 18, 12, 6, ...,
-114 is
(1) 63
(2) -76
(3) -48
(4) -52​

Answer 1

Step-by-step explanation:

nth term of an A.P = a+(n-1)d

-114 = 18+(n-1)-6

-132/6 =(n-1)

n-1 = 22

n = 22+1 = 23

23-12 = 11

a+(12-1)d =18+11(-6)= -48

12th term from the end = -48

Answer 2

nth term of an A.P = a+(n-1)d

-114 = 18+(n-1)-6

-132/6 =(n-1)

n-1 = 22

n = 22+1 = 23

23-12 = 11

a+(12-1)d =18+11(-6)= -48

12th term from the end = -48