12th term from the end of the AP : 18, 12, 6, ...,
-114 is
(1) 63
(2) -76
(3) -48
(4) -52
Answers
Answered by
1
Step-by-step explanation:
nth term of an A.P = a+(n-1)d
-114 = 18+(n-1)-6
-132/6 =(n-1)
n-1 = 22
n = 22+1 = 23
23-12 = 11
a+(12-1)d =18+11(-6)= -48
12th term from the end = -48
fahad4486:
i din't got one part plz explain me that 23-12=11? how?
23 rd term is-114
so 12th term from last is 11
okay thankyou
welcome
Answered by
1
nth term of an A.P = a+(n-1)d
-114 = 18+(n-1)-6
-132/6 =(n-1)
n-1 = 22
n = 22+1 = 23
23-12 = 11
a+(12-1)d =18+11(-6)= -48
12th term from the end = -48
Similar questions