12th term of an ap is -13 and the sum of it's first 4 terms of is 24. Find the sum of it's first 10 terms
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t12=a+11d=-13 ------1
S4=4/2[2a+3d]=25------2
Solve equation 1 and 2
S4=4/2[2a+3d]=25------2
Solve equation 1 and 2
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