Math, asked by himanshuverma94241, 8 months ago

12th term of GP. 2, 4, 6, 8, ------- will be
Generalised term of expansion of (x+a)" is​

Answers

Answered by shaistanazir40
0

Answer:

10

Step-by-step explanation:

because there is two twobadded to no.

Answered by sonuvuce
0

The 12th term of the GP 2, 4, 6, 8, .... is 4096

Step-by-step explanation:

The given GP is

2, 4, 6, ,.....

Here first term of GP is a=2

Common ratio r=\frac{4}{2}=2

We know that if first term of a GP is a and common ratio r[/tex]

Then the nth term is given by

\boxed{a_n=ar^{n-1}}

Therefore, 12th term of the GP will be

a_{12}=2\times (2)^{12-1}

\implies a_{12}=2^{12}

\implies a_{12}=4096

The generalised term (r+1 th term) in the expansion of (x+a)^n is ^nC_rx^ra^{n-r}

Hope this answer is helpful.

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