Math, asked by shaima65, 1 month ago

( 12x^{2}+2x+7)
(12x {}^{2}  + 2x + 7

Answers

Answered by aditi5th
0

Answer:

NO IDEA sorry

Answered by mrnickname50
20

Plz mark brainlist °~•

STEP1:Equation at the end of step 1

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7)

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:(32x2 • (2x + 7)) - 12x • (2x + 7)

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:(32x2 • (2x + 7)) - 12x • (2x + 7) STEP3:Equation at the end of step 3

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:(32x2 • (2x + 7)) - 12x • (2x + 7) STEP3:Equation at the end of step 332x2 • (2x + 7) - 12x • (2x + 7)

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:(32x2 • (2x + 7)) - 12x • (2x + 7) STEP3:Equation at the end of step 332x2 • (2x + 7) - 12x • (2x + 7) STEP4:Pulling out like terms

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:(32x2 • (2x + 7)) - 12x • (2x + 7) STEP3:Equation at the end of step 332x2 • (2x + 7) - 12x • (2x + 7) STEP4:Pulling out like terms 4.1      Pull out     2x+7 

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:(32x2 • (2x + 7)) - 12x • (2x + 7) STEP3:Equation at the end of step 332x2 • (2x + 7) - 12x • (2x + 7) STEP4:Pulling out like terms 4.1      Pull out     2x+7 After pulling out, we are left with :

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:(32x2 • (2x + 7)) - 12x • (2x + 7) STEP3:Equation at the end of step 332x2 • (2x + 7) - 12x • (2x + 7) STEP4:Pulling out like terms 4.1      Pull out     2x+7 After pulling out, we are left with :      (2x+7) • ( 32x2  *  1 +( 12x  *  (-1) ))

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:(32x2 • (2x + 7)) - 12x • (2x + 7) STEP3:Equation at the end of step 332x2 • (2x + 7) - 12x • (2x + 7) STEP4:Pulling out like terms 4.1      Pull out     2x+7 After pulling out, we are left with :      (2x+7) • ( 32x2  *  1 +( 12x  *  (-1) ))STEP5:Pulling out like terms

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:(32x2 • (2x + 7)) - 12x • (2x + 7) STEP3:Equation at the end of step 332x2 • (2x + 7) - 12x • (2x + 7) STEP4:Pulling out like terms 4.1      Pull out     2x+7 After pulling out, we are left with :      (2x+7) • ( 32x2  *  1 +( 12x  *  (-1) ))STEP5:Pulling out like terms 5.1     Pull out like factors :

STEP1:Equation at the end of step 1((9•(x2))•(2x+7))-12x•(2x+7) STEP 2 :Equation at the end of step2:(32x2 • (2x + 7)) - 12x • (2x + 7) STEP3:Equation at the end of step 332x2 • (2x + 7) - 12x • (2x + 7) STEP4:Pulling out like terms 4.1      Pull out     2x+7 After pulling out, we are left with :      (2x+7) • ( 32x2  *  1 +( 12x  *  (-1) ))STEP5:Pulling out like terms 5.1     Pull out like factors :   9x2 - 12x  =   3x • (3x - 4) 

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