Question

12x^2+4x+3=0 by quadratic formula std 10th

Answer 1

Step-by-step explanation:

12x^2+4x+3=0

Here a=12,b=4,c=3

By formula method

b^2-4ac=4^2-4×12×3

=16-144

=128

x=(-b+root b^2-4ac)/2a or (-b-root b^2-4ac)/2a

x=(-4+root 128)/24 or (-4-root 128)/24

x=4(-1+ 2root2)/24 or 4(-1-2root2)/24

x=(-1+2root2)/6 or (-1-2root2)/6