12x^3-7x^2+4x-9=0
factorize it
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QUADRATICS RESOLUTION
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clearly x=1 satisfies the equation hence (x-1) is a factor of the equation and dividing with this we get another factor which is equal to 12x^2+5x+9. hope this helps. I am adding an image too
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DVkhetia:
suppose if there would be two or more factors ... then what to do??
use partition rule to factorise quadratic part. like breaking the middle term containing x
ok thanks
understood perfectly
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