(12x² - 17xy + 6y²) ÷ (3x - 2y)=?l2
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We have, 12x2 – 17xy + 6y2 The coefficient of x2 is 12 The coefficient of x is -17y Constant term is 6y2 So, we express the middle term -17xy as -9xy – 8xy 12x2 -17xy+ 6y2 = 12x2 – 9xy – 8xy + 6y2 = 3x (4x – 3y) – 2y (4x – 3y) = (3x – 2y) (4x – 3y)
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