12xy-4yz-3xz+2x²y+2x²y+2x²z+2yz² x = 1 y= 2 z= 3 find value
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Answer:
We know that,
(a−b−c)
2
=a
2
+b
2
+c
2
−2ab+2bc−2ca
So,
(3x−2y−z)
2
=(3x)
2
+(2y)
2
+(z)
2
−2×(3x)×(2y)+2×(2y)×(z)−2×(z)×(3x)
(3x−2y−z)
2
=9x
2
+4y
2
+z
2
−12xy+4yz−6zx
Step-by-step explanation:
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