Question

12xy-4yz-3xz+2x²y+2x²y+2x²z+2yz²​ x = 1 y= 2 z= 3 find value​

Answer 1

Answer:

We know that,

(a−b−c)

2

=a

2

+b

2

+c

2

−2ab+2bc−2ca

So,

(3x−2y−z)

2

=(3x)

2

+(2y)

2

+(z)

2

−2×(3x)×(2y)+2×(2y)×(z)−2×(z)×(3x)

(3x−2y−z)

2

=9x

2

+4y

2

+z

2

−12xy+4yz−6zx

Step-by-step explanation:

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