Question

12y -1-y^2 =0 in this expression what is the value of y​

Answer 1

firstly multiplying whole equation with -1 to make calculations easier.

we get ,

• y²-12y+1= 0
• applying quadratic formula

[-(-12) ± √ 144-4 ]/ 2

12± √140/2

12±2√35/2

we get now 6±√35

so y can be equal to 6+√35 or 6-√35