Question

12y^2-25y+12 factorise it​

Answer 1

Given: 12y^2 - 25y + 12

12y² - 16y - 9y + 12

On Grouping factors  

(12y² - 16y) - ( 9y + 12)

4y(3y - 4) - 3(3y - 4)

(4y - 3)(3y - 4)

Its zeroes are,

(4y - 3)(3y - 4) = 0

y = 3/4, 4/3

Hope it helps!

Answer 2

Answer:

please refer to the attachment

I hope it would help you

thank you