Math, asked by anitapadidam1, 11 months ago

(12y³-6y²)÷6y² Division of polynomials. How to solve​

Answers

Answered by rajnidahiya66
0

Step-by-step explanation:

12y³-6y²/6y²

(2y-1)6y²/6y²

2y=1

y=1/2

Answered by janhavi38
3

12y3-12y3=0

6y2-6y2=0

divide both the terms by 6y2

the quotient will be 2y-1

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