Question

13?
14?
simplify both ...

Answer 1

Hey friend,
Here is the answer you were looking for:
$13) \\ (3x + 4)(2x - 3) + (5x - 4)(x + 2) \\ \\ = (3x \times 2x - 3x \times 3 + 4 \times 2x - 4 \times 3) \\ + (5x \times x + 5x \times 2 - 4 \times x - 4 \times 2) \\ \\ = ( {6x}^{2} - 9x + 8x - 12) \\ + ( {5x}^{2} + 10x - 4x - 8) \\ \\ = {6x}^{2} - 9x + 8x - 12 + {5x}^{2} + 10x - 4x - 8 \\ \\ = 11x^{2} + 5x - 20 \\ \\ 14) \\ \frac{ {3}^{5} \times {10}^{5} \times 25 }{ {5}^{7} \times {6}^{5} } \\ \\ = \frac{ {3}^{5} \times {5}^{5} \times {2}^{5} \times {5}^{2} }{ {5}^{7} \times {3}^{5} \times {2}^{5} } \\ \\ = \frac{ {2}^{5} \times {3}^{5} \times {5}^{5} \times {5}^{2} }{ {2}^{5} \times {3}^{5} \times {5}^{7} } \\ \\ using \: the \: identity \\ \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} \\ \\ = {2}^{5 - 5} \times {3}^{5 - 5} \times {5}^{5 + 2 - 7} \\ \\ = {2}^{0} \times {3}^{0} \times {5}^{7 - 7} \\ \\ = {2}^{0} \times {3}^{0} \times {5}^{0} \\ \\ = 1 \times 1 \times 1 \\ \\ = 1$

Hope this helps!!!

@Mahak24

Thanks...
☺

Answer 2

this is ur answer....