Question

13. 16 sweets are to be divided between Sahil and Sachin in the ratio 1:3. Find how many sweets each get tell in detail ​

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

Total number of sweets = 16

Let us take x as the common multiple of 1 and 3

So, let no. of sweets with Sahil = 1x and no. of sweets with Sachin = 3x

Therefore we get,

1x + 3x = 16  ------ (1)

      4x = 16

        x= 16/4

So we get the value of x = 4

Now, substituting the value of x in equation (1),

1(4) + 3(4) = 16

4 + 12 = 16

16=16

Therefore RHS = LHS

And hence, no. of sweets with Sahil= 4 and that with Sachin= 12

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