Question

13*2=6
22*10=40
12*21=42
21*31=62
then 62*10=?​

Answer 1

Given sequence :

13*2=6

13*2=6 22*10=40

13*2=6 22*10=40 12*21=42

13*2=6 22*10=40 12*21=4221*31=62

$\red{ To \: find : 62*10}$

/* Observe the sequence we can find following pattern */

$i) 13*2 = (1\times 3 ) \times 2 = 3\times 2 = 6$

$ii) 22*10 = (2\times 2 ) \times 10 = 4\times 10 = 40$

$iii) 12*21 = (1\times 2 ) \times 21 = 2\times 21 = 42$

$iv) 21*31 = (2\times 1 ) \times 31 = 2\times 31 = 62$

$Now, Value \: of \: 62* 10 = (6 \times 2 ) \times 10 \\= 12 \times 10 \\= 120$

Therefore.,

$\red{ Value \: of \: 62* 10}\green { = 120}$

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