Question

1³+2³+3³+4³+.......+10th natural number.

Answer 1

sum of cubes of first n natural numbers =(n (n+1)/2)^2
=(10 (10+1)/2)^2
=(55/2)^2
=3025/4
=756.25

Answer 2

the sum of cubes of n natural numbers is equal to
${ {n(n + 1) \div 2}}^{2}$
here in place of n we have 10
(10(10+1)/2 )square
$= {55}^{2} = 3025$