Question

1³ 2³ 3³ ......99³ last digit number

Answer 1

HERE IS YOUR ANSWRR

Use the identity

a³+b³=(a+b)(a²−ab+b²) Hence,,

a³+(99−a)³=99[a²−a(99−a)+(99−a)²] That is, each of the pairs 13+983,23+973,…493+503 is divisible by 99 . Since 993 is also divisible by 99 , so is the sum.

Hope it helps U

Thnxs