Question

1³+2³+3³+...+k³=44100 then find 1+2+3+...+k

Answer 1

Solution:

1³+2³+3³+...+k³=44100

=> [k(k+1)/2]² = (210)²

=> [k(k+1)]/2 = 210 ---(1)

1+2+3+...+k = [k(k+1)]/2

= 210 [ from (1) ]

••••

Answer 2

Answer:

Step-by-step explanation:

1 + 2 + 3 + ....... + n = n(n + 1) / 2

1^3 + 2^3 + 3^3 + ..... + n^3 =

= [n(n + 1) / 2]^2

1 + 2 + 3 + ..... + n =

= sqrt(1^3 + 2^3 + .... + n^3)

= sqrt(441 00)

= 210.