Question

1³+2³+3³....+n³= [n(n+1)/2]²​

Answer 1

Answer:

1^3+2^3+3^3-..........n^3

nth term of 1+2+3........n

a+(n-1)d

1+(n-1)1

1+n-1

n

Now nth term for 1^3+2^3+3^3........n^3

n^3

now ,

Σn^3

[n(n+1)/2]^2

Explanation:

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