Question

13. 28+ [32 - 16 of (15-6 x 2)​

Answer 1

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$= 28+ [32 - 16 \: of (15-6 \times 2)] \\ = 28+ [32 - 16 \: of (15-12)] \\ = 28+ [32 - 16 \: of \: 3] \\ = 28+ [32 -48] \\ = 28 - 16 \\ = 12$

Answer 2

Answer:-

28+[32-16 of (15-6×2)]

=28+[32-16 of (15-12)]

=28+[32-16 of 3]

=28+[32-48]

=28-16

=12

The required answer is 12