Question

_,13,_,3 is an arthemetic progression find _​

Answer 1

Answer:

Given: a2 = 13 and a4 = 3 We know that, an = a + (n – 1)d a2 = a + (2 – 1)d 13 = a + d …(i) and a4 = a +(4 – 1)d 3 = a + 3d …(ii) Solving linear equations (i) and (ii),

we get a + d – a – 3d = 13 – 3 ⇒ –2d = 10 ⇒ d = –5 Putting the value of d in eq.

(i), we get a – 5 = 13 ⇒ a = 18 Now, a3 = a + 2d = 18 + 2(–5) = 18 – 10 = 8

Hence, the missing terms are 18 and 8.