Question

1³+3³+5³+......to n terms.​

Answer 1

Answer:

$1^{3}+3^{3}+5^{3}.....n terms. \\ =>1,3,7.... \\ Tn = a(n-1)2 \\ => Tn= 1+(n-1)2 \\ => tn= 1+2n-2 \\ =>tn =2n-1 \\ 1^{3}+3^{3}+5^{3}........+2n-1 \\ tn =(2n+1)^{3} \\ => sn= sigma (tn) \\ => sigma = (2n+1)^{3} \\ => sigma = (8n^{3}+1+3(4n^{2})(1+3)(2n (1) ) \\ => sigma = (8n^{3} +12n^{2}+6n+1) \\ 8sigma (n)^{3}+12sigam (n)^2}+6sigma(n)+1 sigma \\ <u>=</u><u>></u> 8[n \frac{ {n+1} }{ {2} }]^{2} + 12(n(n+1)(2n+1)/2 +6\multin[\frac{ {n+1} } {2}] + 1n$.

Answer 2

Answer:

${1}^{? \\ 2 \leqslant \div {x { \frac{ { \frac{ \frac{y)(yx { { \frac{ \sqrt{ \sqrt[ | < > \div \times - + 9871453.26| ]{?} } \times \frac{?}{?} }{?} }^{?} }^{2} \times \frac{?}{?} }{?} }{?} }^{2} \times \frac{?}{?} }{?} }^{2} }^{?} \times \frac{?}{?}$