Question

13√3x²+10x+√3 :quadratic equation the nature root

Answer 1

d=b2-4ac
d=100-4×13√3×√3
d=100-156
d=-56
As d<0
the zeroes are not real

Answer 2

a = 13√3 , b = 10, c = 3  

b^2 – 4ac = (10)^2 – 4(13√3)(3)

= 100 – 156

= – 56  

As b^2 –4ac < 0

So, the equation has no real roots