Physics, asked by Rudra788, 1 month ago

13.5 mL of a solution, made by mixing 6 g of a monobasic acid (mol. mass = M) in 1 L H20, was completely neutralised by 10 mL of a decinormal Ca(OH)2 solution. Then VM is Answer: 00 01 02 03 04 05 06 07 08 09 Select your answer from radio buttons.​

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Answered by s23837
4

Answer:

13.5 mL of a solution, made by mixing 6 g of a monobasic acid (mol. mass = M) in 1 L H20, was completely neutralised by 10 mL of a decinormal Ca(OH)2 solution. Then VM is Answer: 00 01 02 03 04 05 06 07 08 09 Select your answer from radio buttons.

Answered by adventureisland
0

The completely neutralised by the molar mass 162.

Explanation:

N_{1}V_{1}(acid)=N_{2}V_{2}(base)

N_{1}*13.5=\frac{1}{10}*10

N_{1}=\frac{1}{13.5}

Strength=N*E_{w}

6=\frac{1}{13.5}*E_{w}

E_{w}=81

Molar mass=Equivalent*Basicity

=81*2

=162.

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