Physics, asked by manaswini25, 10 months ago

13.63 D
22).
A radiation of wavelength 5400 Å falls on a metal with work function 1.9 eV. Find
the energy of photo electrons emitted
1) 0-4 eV
2) 2-3 eV
3)0.4 V
4) 2:3 V
emitted​

Answers

Answered by Rohith200422
1

Answer:

Work \: function \: of \: plate  ϕ=1.9 e \\ Wavelength \: of \: incident \: photon \: λ=5000 \: Ao=500 nm \\ Energy \: of \: the \: incident \: photon \:   Eincident \: =λ \: (in nm) \: 1240 eV  \\ ⟹ Eincident \: = \: 5001240 \: = \: 2.48 eV \\ Maximum kinetic \: energy \: of \: photon \: emitted \\ K.Emax \: = \: Eincident−ϕ</p><p> \\ ⟹ K.Emax \: =2.48−1.9 = 0.58 eV

Maximum \: kinetic \: energy \: of \: photon \: emitted \: is \: 0.58eV.

I \: hope \: this \: helps \: you

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