13+[7×(-3)]=[25×4]+[18-3]
Answers
Answer:
bro it is in book so refer the example sum
Step-by-step explanation:
okay aa bro try it its in book
So, multiplication is commutative, and addition is commutative. By standard policy, we do multiplication prior to addition. But first, we work brackets from the inside out.
So, since we have some brackets, let’s put in more brackets so you can more easily see what goes in what order.
Oh, and while we’re here, note that “of” is an English language word indicating multiplication.
4 of [25-18÷ {7-2 of 3-(13-4-3) +5}]
Innermost, we have 13–4–3. This is addition, so it doesn’t matter what order we do it in, although traditionally we go left to right. 13–4 is 9, 9–3 is 6
So now we go to the next bracket out, the {} ones. Here we see 7–2*3–6+5 (subbing in the 6 for the innermost bracket, and * for the word “of”)
We’re going to do multiplication first, so that’s 7-(2*3)-6+5 which is to say 7–6–6+5. Again left to right for no particular reason, 7–6 is 1, 1–6 is -5, -5+5 is 0
Next out we have the [] brackets. That’s 25–18÷0, subbing in the result of the {} brackets. We do the multiplication first, so we’re at 25-(18÷0) and oops, full stop.
Division by zero is undefined. There is no result. We can’t subtract undefined from 25, and we’re not going to be able to multiply that total by 4 when we get outside the [] brackets, because everything blew up already.
So the answer is, sorry, you can’t solve that