Question

–13.7 kcal/mol is the heat of neutralisation of

Answer 1

Answer:

13.7 kcal mol is the heat of neutrasation of enthepy

Answer 2

Answer:

1) In the neutralization process ions come to each other and form salt and water.

2) HCL is strong acid means H

+

+CL

−

and NaOH is strong base means Na

+

+OH

−

So there is not any energy loss to break HCL or NaOH. total energy will come as neutralisation.

3) In Case of NaOH+CH

3

COOH NaOH is strong base means Na

+

+OH

−

But CH

3

COOH is a weak acid so have to give some energy to form CHCOO

−

+H

+

So total released energy= total energy in case of (strong acid + strong base) - energy require to form ions. 3.7=13.7 - energy require to form ions energy require to form ions=10.00kcal. only CH

3

COOH is weak nature So this enegy is ionisation energy of CH

3

COOH.

Explanation:

hope it's help you friend.

THANK YOU.

sorry for late answering....