–13.7 kcal/mol is the heat of neutralisation of
Answers
Answer:
13.7 kcal mol is the heat of neutrasation of enthepy
Answer:
1) In the neutralization process ions come to each other and form salt and water.
2) HCL is strong acid means H
+
+CL
−
and NaOH is strong base means Na
+
+OH
−
So there is not any energy loss to break HCL or NaOH. total energy will come as neutralisation.
3) In Case of NaOH+CH
3
COOH NaOH is strong base means Na
+
+OH
−
But CH
3
COOH is a weak acid so have to give some energy to form CHCOO
−
+H
+
So total released energy= total energy in case of (strong acid + strong base) - energy require to form ions. 3.7=13.7 - energy require to form ions energy require to form ions=10.00kcal. only CH
3
COOH is weak nature So this enegy is ionisation energy of CH
3
COOH.
Explanation:
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