13.8g of Ag2CO3 is strongly heated. Its released gases are used for combustion of C2H2, the number of moles of C2H2 oxidised are : (Molecular weight of Ag2CO3 = 276)
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Answer:
0.02
Explanation:
ag2co3 = 2ag+ o2 +co2
276 grams of ag2co3 gives 32 grams of oxygen
13.8grams of ag2co3 gives 1.6 grams of oxygen
ie, 0.05 moles of oxygen
for combustion of c2h2
c2h2 + 5/2o2 = 2co2 + h2o
1 mole of c2h2 needs 5/2 moles of oxygen
x moles c2h2 needs 0.05 moles of oxygen
x = 0.02 moles of c2h2
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