Question

13. A 500kg boat has an initial speed of 10ms as
it passes under a bridge. At that instant a 50 kg
man jumps straight down into the boat from the
bridge. The speed of the boat after the man and
boat attain a common speed is
100​

Answer 1

Dear Student,

◆ Answer -

v = 100/11 m/s

● Explaination -

# Given -

M = 500 kg

m = 50 kg

u = 10 m/s

# Solution -

According to law of conservation of momentum,

Pi = Pf

Mu = (M+m)v

500 × 10 = (500+50) × v

v = 5000 / 550

v = 100/11 m/s

v = 9.09 m/s

Therefore, speed of the boat after man jumps into it is 100/11 m/s.

Thanks dear...

Answer 2

Answer:

Explanation:According to law of conservation of momentum,

Pi = Pf

Mu = (M+m)v

500 × 10 = (500+50) × v

v = 5000 / 550

v = 100/11 m/s

v = 9.09 m/s

Therefore, speed of the boat after man jumps into it is 100/11 m/s