Question

13. (a) a+b+c = 6 and ab+bc+ca = 11, find a²+b²+c² .​
chapter expansion of powers of binomials and trinomials.

Answer 1

Answer:

14

Step-by-step explanation:

Using the identity,

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

Rearranging,

a²+b²+c²=(a+b+c)²-2(ab+bc+ca)

              =6²-2(11)

              = 36-22

              = 14

Answer 2

Answer:14

Step-by-step explanation:

a+b+c = 6...................1

square .......it

a²+b²+c² + 2ab + 2bc + 2ca=36

a²+b²+c² +2(ab+bc+ca)=36

a²+b²+c²+22=36.....................(ab+bc+ca = 11)

a²+b²+c²=14

mark it brainliest