Question

13. A alone can do a piece of work in 12 days and B alone can do the same work in
15 days. A works alone for 4 days. In how many days will A and B together finish
the remaining work ?
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Answer 1

Step-by-step explanation:

Let the work be assumed to have 60- parts (LCM of 12 and 15 is 60)

So in 1- day A can do=60/12= 5- parts

B can do in 1- day= 60/15= 4- parts

In 1- day both can do= 9- parts.

So in 4- days they can do= 9 x4= 36 parts.

Now the remaining part of (60–36)= 24 parts is done by A alone.

So Number of days required by A to do the remaining work of 24- parts =24/5= 4.8 days.

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