13. A ball is dropped from certain height such that the
distance travelled in last second is equal to the
distance travelled in first three second. Find its height
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Answer: Hello! This may help you for sure!
Formula used:
sn=u+g/2(2n−1)
Answer:125m
Explanation:
The distance covered in first 3 second
s=1/2gt^2
=1^2×10×3^2
=45
Ball takes 'n' seconds to fall to the ground. The distance covered in the nth second is
sn=u+g/2(2n−1)
=10/2(2n−1)
=10n−5
Therefore 45=10n−5
n=5=t
Therefore h=12*gt^2
=12×10×25
=125m
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