Question

13. A ball is thrown vertically
upwards from the top of a
tower with an initial velocity of
20 m/s. The ball reaches the
ground after 6 s. Calculate
(i)the height of the tower
(ii)the velocity of the ball on
reaching the ground, Take
g=10m/s^2.

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Answer 1

Answer:

Step-by-step explanation:

consider upper direction as positive

-h=ut-1/2*g*t²

-h=20*6-1/2*10*36

-h=120-180

h=60m

(ii) -v=u-gt

-v=20-10*6

-v=-40

v=40 m/s

Answer 2

Answer:

(i) 60 m

(ii) 40 m/s

Step-by-step explanation: