13. A bar of gold is found to have a mass of 100 g and weight of 0.981 N at some place. When this
bar is taken to a place on the equator, it is found that the mass remains 100 g, but the weight is
less than 0.981 N. Explain the above observation.
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(i) The mass of the gold bar is a constant quantity, and hence, will remain same anywhere and everywhere.
(ii) The weight of the gold bar decreases because the acceleration due to gravity is least at the equator. As the weight is the product of mass and acceleration due to gravity, therefore, its value decreases at the equator.
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A bar of gold is found to have a mass of 100 g and weight of 0.98 N at some place. When the bar is taken to some place at the equator, it is found that the mass remains 100 g, but the weight is less than 0.98 N. Explain the above observations.
(i) The mass of the gold bar is a constant quantity, and hence, will remain same anywhere and everywhere.
(ii) The weight of the gold bar decreases because the acceleration due to gravity is least at the equator. As the weight is the product of mass and acceleration due to gravity, therefore, its value decreases at the equator.
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