Question

13. A body is projected from the ground with a velocity of 20 m/s at an angle of 600 with the
horizontal. Find its speed at the highest point.
Ans. 10 m/s​

Answer 1

Answer:

The answer (10) is true.

Explanation:

At the peak (highest) point the vertical velocity (Vy) of a projectile becomes Zero. Only the horizontal velocity is left which remain constant throughout the motion.

THUS V = Vx = Vcosθ = 20cos60 = 20(1/2) = 10m/s

:. cos60 = 1/2