Question

13. A boy first goes 5 m due north and then 12 m due east. Find the distance between the initial and the final positions of the boy.
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Answer 1

Answer:

13 m

Step-by-step explanation:

let the distance between the initial and final point be x

then,

x^2= 5^2+12^2

=25+144

=169

x=square root of 169

x=13

Answer 2

Here it is given that a boy first goes 5 m due north and then 12 m due east.

We have to find the distance between the final and initial position

This can be done by vector addition

First, the boy moves 5 m towards the north, the vector will be 5j

Then the boy moves 12 m towards the east, the vector will be 12i

Distance = 5j + 12i

Magnitude = $\sqrt{5^{2} + 12^{2} }$

                 = $\sqrt{169}$

                 = 13

So, the distance between initial and final position will be 13 m.