Question

13. A bus can be stopped by applying a retarding force F when
it is moving with speed v on a level road. The distance
covered by it before coming to rest is s. If the load of the
bus increases by 50% because of passengers, for the same speed and same retarding force , the distance covered by the bus to come to rest shall be
(a) 1.5 s
(b) 2s
(c) 1s
(d) 2.5 s​

Answer 1

★ Hello!....Hari....★

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Have a look for your answer.....

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Let,

mass loaded in bus = m

Velocity of bus = v

Initial distance = s

Final distance s'

Force = F

Now,

==> In frist case.....

F force is applied to stop the bus.

Work done by the bus is equal to it's kinetic energy.

So,

K.E = Work [K.E = 1/2mv², work = Force×distance]

Then,

1/2mv² = Fs.................eq (1)

==> In 2nd case....

Due to increased bus load by 50%,

1/2(m+m/2)v² = Fs'..................eq (2)

By equating both equations, we get

s'/s = 3/2

s' = (3/2)s

s' = 1.5s

Thus, the distance covered by bus to come in rest would be 1.5s

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Yeah! Your option (1) is the correct answer.

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Hope it will help you ✌️

Thanks!☺️

Answer 2

Answer:

a) 1.5 s is correct answer