Question

13. A car accelerates from 6 ms-1 16 m -1in 10 sec. Calculate
(a) the acceleration and
(b) the distance covered by the car in that time.​

Answer 1

given

Vf= 16m/s

Vi= 6m/s

time= 10s

a= (Vf-Vi)/time

= (16-6)/10

= 1m/s^2

Distance,S= ut+1/2 at^2

= 6•10 + 1/2•1•10^2

= 60+50 = 110m