Question

13.
A car accelerates from 6 ms to 16 ms in 10 sec. Calculate
(a) the acceleration and
(b) the distance covered by the car in that time.​

Answer 1

ANSWER

A.

one metre per second square

B.110m

Answer 2

Answer:

A.1m/s^2

B.110m

Explanation:

A.

u=6m/s

v=16m/s

a=v-u/t

=16-6/10

=10/10

=1m/s^2

B.

using v^2-u^2=2aS

16^2-6^2=2×1×S

256-36=2S

220=2S

220/2=2S

110=S

distance=110m

☆☆☆☆☆☆