Question

13. A circular flower bed is surrounded by a path 4m wide. The diameter of the flower
bed is 66 m. What is the area of this path? (π=3.14)​

Answer 1

Answer:

778.8m²

Step-by-step explanation:

radius =diameter of flower bed÷2

r=66÷2

r=33

Area of the whole flower bed=(3.14)(33²)

                                                =3419.46≅3419.5m²

radius of inner circle=33-4=29

Area of inner circle=(3.14)(29²)

                                =2640.74≅2640.7m²

Area of the path or the outer circle=3419.5-2640.7

                                                              =778.8m²

Answer 2

Given:-

Width of the path = 4 m

Diameter of the flower bed = 66 m

To find:-

The area of the path.

Solution:-

Diameter of the flower bed is 66 m.

So, Radius of the flower bed =diameter/2

= (66/2)m

= 33m.

Now, Area of flower bed =  π r²

⟹ Area = 3.14 × (33)²

⟹Area = 3.14 × 1089.

⟹Area = 3419.49 m²

Now, Diameter of large circle

= Width of path + diameter of flower bed.

= ( 66 + 4)m

= 70m

So, Radius of large circle

= (diameter/ 2)

= (70/2)m

= 35 m.

Now, Area of large circle =  π r²

➟Area = 3.14 × (35)²

➟Area = 3.14 × 1225.

➟Area = 3846.5

So, now Area of path

= Area of large circle - Area of flower bed

= 3846.5 - 3419.49

= 427.01 m² (ans)

Therefore, the area of the path is 427.01 m².

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