Math, asked by vinodbandgar550, 5 months ago

13. A circular pond is surrounded by a 2 m wide circular path. If outer circumference of circular
path is 44 m, find the inner circumference of the circular path. Also, find area of the path.

Answers

Answered by Anonymous
139

⠀⠀⠀⠀⠀⠀⠀{\huge{\underbrace{\rm{Question}}}}

A circular pond is surrounded by a 2 m wide circular path. If outer circumference of circular path is 44 m, find the inner circumference of the circular path. Also, find area of the path.

⠀⠀⠀⠀⠀⠀⠀⠀{\huge{\underbrace{\rm{Answer}}}}

Given:

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  • The circular pond is surrounded by a 2 m wide circular path.

  • The outer circumference of circular path is 44 m

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To find:

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  • find the inner circumference of the circular path.

  • Also, find area of the path.

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Solution:

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Let the inner radius of the path is ' r '

As the circular path is 2 m wide.

So, the outer radius of the path is (r + 2)

.°. The outer circumference = 2π (r + 2)

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According to the question ,

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⠀⠀⠀⠀⠀\sf{:\implies 2π(r+2)=44}

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⠀⠀⠀⠀⠀\sf{:\implies 2×\dfrac{22}{7}(r+2)=44}

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⠀⠀⠀⠀⠀\sf{:\implies (r+2)=\dfrac{7}{22}×\dfrac{1}{2}×44}

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⠀⠀⠀⠀⠀\sf{:\implies (r+2)=7}

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⠀⠀⠀⠀⠀\sf{:\implies r=7-2}

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⠀⠀⠀⠀⠀⠀\boxed{\bf{\pink{:⟹\:r\:=\:5}}}

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NOW,

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The inner circumference of the path is

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⠀⠀⠀⠀⠀\sf{:\implies 2πr}

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⠀⠀⠀⠀⠀\sf{:\implies 2×\dfrac{22}{7}×5\:m}

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⠀⠀⠀⠀⠀\sf{:\implies \dfrac{220}{7}\:m}

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⠀⠀⠀⠀⠀\sf{:\implies 31.43\:m}

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Therefore,

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\dashrightarrow\:\:\underline{\boxed{\sf the\:inner\:circumference\:of\:the\:path=31.43\:m}}

Now,

Area of the circular path is

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⠀⠀⠀⠀⠀\sf{:\implies π(r+2)^{2}-πr^{2}}

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⠀⠀⠀⠀⠀\sf{:\implies \dfrac{22}{7}×[(5+2)^{2}-5^{2}]m^{2}}

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⠀⠀⠀⠀⠀\sf{:\implies \dfrac{22}{7}×[49-25]\:m^{2}}

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⠀⠀⠀⠀⠀\sf{:\implies \dfrac{22}{7}×24\:m^{2}}

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⠀⠀⠀⠀⠀\sf{:\implies \dfrac{24×22}{7}\:m^{2}}

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⠀⠀⠀⠀⠀\sf{:\implies {\cancel{\dfrac{528}{7}}}\:m^{2}}

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⠀⠀⠀⠀⠀\sf{:\implies 75.43\:m^{2}......(approx)}

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Hence,

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\dashrightarrow\:\:\underline{\boxed{\sf area\:of\:the\:circular\:path\:=\:75.43\:m^{2}.....(approx)}}

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