Math, asked by nagrapratham, 3 months ago

13. A die is tossed once, find the probability of getting 3.
2
1
(b)
(c)
(d)
2
6
6​

Answers

Answered by honalu14
1

Answer:

Step-by-step explanation:

possible outcomes ={ 1,2,3,4,5,6} no.=6

favorable outcomes = {3,6} no.=2

∴Probability = no. of favorable outcomes / no. of possible outcomes

                   =2/6

                   = 1/3 (simplified)

hope it helps you!!

Answered by harshitadixit11
0

1/6

Step-by-step explanation:

let denote event=P

total no of outcomes=6

favourable no =1

favourable outcomes/total outcomes

hence (p)=1/6

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