Question

13. A floor of a building consists of 2,500 tiles. All the tiles are rhombus shaped with diagonal
40 cm and 25 cm. Find the total cost of polishing the floor at the rate of ₹8 per square meter.​

Answer 1

$\huge\underline\mathcal\red{SOLUTION}$

Given:-

Total no. of tiles =2550

Since the tiles are in the shape of rhombus and diagonals are of length 20cm and 28cm.

Therefore,

$d1 = 20 \\ d2 = 28$

Area of one tile = Area of rhombus

As we know that area of rhombus is given as-

$\frac{1}{2} \times d1 \times d2$

Therefore,

$area \: of \: 1 \: tile = \frac{1}{2} \times 20 \times 28 = 280 {cm}^{2}$

∴ Area of 2550 tiles =2550×280=714000cm^2

=71.4m^2

Given that the cost of polishing is Rs.25 per m^2

Therefore,

Cost of polishing the floor =25×71.4=Rs.1785

Hence the cost of polishing the floor is Rs.1785.

$\huge\underline\mathcal\purple{BTS \: EXO}$